wanganhong

I got it! Used: ``` aggs1 = Aggregate.date_histogram('results', 'time', 'day') aggs2 = Aggregate.children('to-child', 'status') aggs3 = Aggregate.terms('inner', 'handle_flag') aggs2.aggregate(aggs3) aggs1.aggregate(aggs2) print aggs1.dict() ``` Is there a simpler way?