Han Jiang
Han Jiang
Yeah, I understand that the result is always near the error boundary. Just to make sure the codes express the intention clearly. And no, the algorithm is not right, simply...
> That doesn't satisfy the invariant I mentioned in the comment Ah I see, sorry I didn't understand the term `invariant` previously. I don't know in real case whether we'll...
Thanks for the link, I'll check it later. Yes, your algorithm is right if the invariant is true. My point is that, we cannot always assert that the real data...
> > For example edge cases sush as error(i) == error(j) > > This is not an edge case, and the algorithm still works. Oh, to clarity, I meant it...
to reproduce this bug: bdwm.net/bbs