filatovzru

i have bridged by webhook https://lru0.webhook.office.com/webhookb2/2e0e86e5-ab07-4519-9bd1-c4d4aea2b167@8590acc3-70b3-4c2d-a3ff-566504ef2738/IncomingWebhook/56b74632b7aa43f49e455fdf5d2524d/38991207-c099-494b-838d-f22dc73e4933

yes, this webhook as example! MS Teams [have](https://docs.microsoft.com/en-us/microsoftteams/platform/webhooks-and-connectors/what-are-webhooks-and-connectors) outgoing and incomming webhoks [Example by JS from zabbix_template](https://git.zabbix.com/projects/ZBX/repos/zabbix/browse/templates/media/mattermost/media_mattermost.yaml?at=release/6.0)

> Получил токен через https://oauth.vk.com/authorize?client_id=приложение&display=page&redirect_uri=https://oauth.vk.com/blank.html&response_type=token &scope=wall,offline ручками и передал его: vk_session = vk_api.VkApi(token=acc_token) >еще добавил, на всякий случай: vk_session.http.headers[ 'User-agent'] = 'Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:94.0) Gecko/20100101 Firefox/94.0'...

Удалось починить вот таким методом, с предварительным удалением `vk_config.v2.json` ```python vk_session = vk_api.VkApi( login=settings.VK_LOGIN, password=settings.VK_PASSWORD, ) try: vk_session.http.headers['User-agent'] = 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10.15; rv:94.0) Gecko/20100101 Firefox/94.0' vk_session.auth(token_only=True)...

How i can? Please tell me...

Очень хотелось бы!

Пока вышел из положения таким способом: ``` function substCallback(p){ if(p){ $('.ct_phone').attr('href','tel:'+p.phone[0]); $('.ct_phone_2').attr('href','tel:'+p.phone[1]); }else{ } }``` ` sipuniCalltracking({ targets: ['.ct_phone', '.ct_phone_2'], callback: substCallback, ...`

Yes, but `Detected a shared secret for` search by password or any text in vault file?

I have comand to remove all duplicates

👍