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                                            k3ck3c

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I can translate to french

is there a neat way to find the output filename when using --restrict-filenames -o "%(channel)s-%(title)s.%(ext)s"

Thanks for the answer as it seems I can't export variables from --exec I will stick to my script lang="${2:-fr}" outfile=$(yt-dlp --restrict-filenames -o "%(channel)s-%(title)s.%(ext)s" -x --audio-format mp3 "${1}" | grep...

is there a neat way to find the output filename when using --restrict-filenames -o "%(channel)s-%(title)s.%(ext)s"

not sure what the correct syntax should be when I download I get the message [ExtractAudio] Destination: Aurelien_Blondel_-_Trading-BOURSE_A.T._24-02-25_-_Resultats_CAC40_Microsoft_affole_les_marches_agenda_croissance_US_Alibaba.mp3 so I modified my command yt-dlp --exec echo "[ExtractAudio] Destination: {} mp3"...

is there a neat way to find the output filename when using --restrict-filenames -o "%(channel)s-%(title)s.%(ext)s"

I can't get a valid command ```$ yt-dlp -vＵ-exec echo ’”Destination: {} .mp"’ --restrict-filenames -o "%(channel)s - %(title)s.%(ext)s" -x --audio-format mp3 'https://www.youtube.com/watch?v=OSePcHBt2vA"' bash: erreur de syntaxe près du symbole inattendu...

is there a neat way to find the output filename when using --restrict-filenames -o "%(channel)s-%(title)s.%(ext)s"

excellent! both solutions work great, thanks a lot