Derk Norton

Results 8 comments of Derk Norton

I vote for option 1 ([Riemann Sphere](https://en.wikipedia.org/wiki/Riemann_sphere)) that @balagge recommended. It is both mathematically and programmatically elegant and shouldn't add much if any to the size of the library. I...

My understanding is that all mathematical operations that work in the complex plane work the same way on the Riemann sphere. So the results of complex exponential operations that land...

Since z^n is the same as z * z * ... * z and Infinity * Infinity => Infinity I would say the answer should be Infinity. > On Mar...

I think Harry was asking about Infinity^z rather than z^Infinity. The first should be Infinity. I think you are correct that the second should be indeterminate (NaN). > On Mar...

Sorry, my mistake... > On Mar 9, 2018, at 11:29 AM, Harry Sarson wrote: > > @derknorton Both cases are relivant but to clarify: > > Complex(Infinity).exp() calculates e^Infinity so...

I think #3 should result in Infinity for |z| > 1 > On Mar 9, 2018, at 11:36 AM, Harry Sarson wrote: > > To summarise for complex z :...

That's fine, but we should clarify (especially in the code) that for real z the third one approaches Infinity for |z| > 1 ;-) > On Mar 9, 2018, at...

> On Mar 14, 2018, at 5:46 PM, Harry Sarson wrote: > > To summarise for any complex z: > > z ^ Infinity === NaN > Infinity ^ z...