Adam Kucharski

Results 23 comments of Adam Kucharski

Thanks for the response. It looks like it is eventualy loading, but required quite a lot of time for me (~10 mins on MacBook Air). A follow up question I...

Thanks. I've updated to 0.3.2. Profiling the above steps, `download_survey("https://zenodo.org/doi/10.5281/zenodo.4905745", "comix_data")` took me 16s and`load_survey(survey_files)` took 6.4 mins

Reinstalled that dev version. Profiling the above steps, `download_survey("https://zenodo.org/doi/10.5281/zenodo.4905745", "comix_data")` took me 29s and `load_survey(survey_files)` took 43s – much quicker for the latter!

Agree would be nice to think about generalisations, especially if there are modular components that could be reused. In case helpful to inform plans, a couple of related efforts: -...

A version of this problem came up in a recent discussion with simulist (https://github.com/epiverse-trace/simulist/issues/58), when we wanted to incorporate simulation of contacts as well as secondary cases into [epichains](https://github.com/epiverse-trace/epichains/). This...

Wonder if there's any functionality from {epidemics} that might be useful here in wrapping up parameters to pass to model (maybe just for alignment in styles, rather than taking on...

That makes sense. Regardless of design choice, would also be useful to have ability to pass distributions like incubation period and estimates of k etc. from {epiparameter} (and {epireview} once...

✨✨ Here's [an AI-assisted sketch of how you might approach this issue](https://copilot-workspace.githubnext.com/epiverse-trace/epiparameter/issues/310?shareId=dd0685d1-3678-491b-a6bb-70b71d2809d0) saved by @adamkucharski using Copilot Workspace v0.19 Topic Does the `as_epidist` function allow attaching an estimated distribution to...

Also found an error with Ebola parameter with exponential distribution: ```r # Load Ebola data data_in 50 params_in

There are two parts to the loss function above. One minimises the least square residual for the median, i.e. `(F(median) - 0.5)^2` and the other is based on the probability...