LinearRegression.jl
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Simple & fast linear regression in Julia
Hi, I am a newbie to Julia, and I ran into this problem when trying to do a linear regression to two data arrays. Could you please give me more...
I had problems running linregress with intercept=false. This constructor worked: LinearRegression.LinearRegressor(intercept::Bool, coeffs::Float64) = LinearRegression.LinearRegressor(intercept, [coeffs]) I guess you could also swap ::Float64 with ::Real.
Hi, I would like to predict the model on a dataset. Here is what I tried, I thought it was supposed to work according to the readme: ``` x =...