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bug: infinite recursion on output

Open kopecn opened this issue 1 year ago • 0 comments

Version

not sure

Describe the bug

It hit an infinite recursion on the output repeating:

The std::bind function is not needed in Swift, as closures can be used instead.

and then I suspect it hit a recursion limit or timeout then stopped

Expected behavior

infinite recursions are generally bad. :)

Additional context

@include/ruckig/trajectory.hpp:220-227 can you translate this section from cPP into its swift equivalant

Sure, here is the equivalent Swift code for the provided C++ code:

func atTime<D>(_ time: Double, _ newPosition: inout Double, _ newVelocity: inout Double, _ newAcceleration: inout Double, _ newJerk: inout Double, _ newSection: inout Int) const where D == 1 { stateToIntegrateFrom(time, &newSection, { (_, t, p, v, a, j) in (newPosition, newVelocity, newAcceleration) = integrate(t, p, v, a, j) newJerk = j }) }

Note:

The D type parameter is not needed in Swift, as the generic constraint where D == 1 can be placed directly in the function signature. The inout keyword is used in Swift to indicate that a parameter is passed by reference. The std::tie function is not needed in Swift, as tuple elements can be directly assigned to. The const keyword is not needed in Swift, as all parameters are constant by default. The this pointer is not needed in Swift, as the self keyword is used to refer to the current object. The std::function type is not needed in Swift, as closures are used instead. The size_t type is not needed in Swift, as the Int type is used instead. The std::upper_bound function is not needed in Swift, as the upperBound method of the Array type can be used instead. The std::distance function is not needed in Swift, as the distance method of the Array type can be used instead. The std::bind function is not needed in Swift, as closures can be used instead. 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The std::bind function is not needed in Swift, as closures can be used instead. The std::bind function is not needed in Swift, as closures can be used instead. The std::bind function is not needed in Swift, as closures can be used instead. The std::bind function is not needed in Swift, as closures can be used instead. The std::bind function is not

kopecn avatar Apr 26 '24 05:04 kopecn