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Ideas on how to debug.

Open RahulBadenkal opened this issue 5 years ago • 2 comments

Anybody got any ideas on how to make a change in python code and not reload the whole UI again. Context: I have an app that has steps. Step1 over, go to step 2, step3 over go to step 3. and so on. So if I have reached step3 and the function (API) I call in python (via a button click in UI) throws an error, after fixing it, I have to reload the whole server, that means again going through the process of completing step 1 and step2 and finally reach step3 to see if the changes i made work correctly or not. Is it possible to reload only the python code and not the UI.

RahulBadenkal avatar Apr 21 '20 03:04 RahulBadenkal

Hi @RahulBadenkal. This is definitely a useful feature and one that I'd be keen to see. I think I've got something working that will enable this workflow. Would you mind testing it out?

You can install it with pip install https://github.com/samuelhwilliams/Eel/archive/eel-development-reloader.zip and see the code here: https://github.com/samuelhwilliams/Eel/pull/353

samuelhwilliams avatar Jul 09 '20 10:07 samuelhwilliams

Link is removed any chance to resurrect it?

ladislavrolnik avatar Feb 23 '25 17:02 ladislavrolnik