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Polars timezone not respected in graph_objects.scatter

Open kevinleahy-switchdin opened this issue 7 months ago • 1 comments

latest version of plotly // python 3.12

from datetime import datetime, timedelta
from zoneinfo import ZoneInfo

import pandas as pd
import polars as pl

daterange = [datetime(2023, 1, 1, tzinfo=ZoneInfo("Australia/Brisbane")) + timedelta(hours=i) for i in range(48)]

df_1 = pl.DataFrame(
    {
        "timestamp": daterange,
        "line1": [0.1] * 24 + [0.2] * 24,
    }
)
df_2 = pl.DataFrame(
    {
        "timestamp": daterange,
        "line2": [0.0] * 24 + [0.4] * 24,
    }
)
fig = px.line(df_1, x="timestamp", y="line1")

fig.add_trace(
    go.Scatter(
        x=df_2["timestamp"],
        y=df_2["line2"],
        name="line2",
    )
)
fig.show()

"line1" (using px.line )renders correctly with local time on the X-axis. But "line2" (using go.Scatter) gets converted to UTC.

This goes away if df_2 uses pandas or I pass in df_2['timestamp'].to_list() instead.

Probably related to https://github.com/plotly/plotly.py/issues/5166 - is this just because polars isn't supported, but since we've not got type hints in plotly my IDE wasn't complaining?

kevinleahy-switchdin avatar Jun 10 '25 13:06 kevinleahy-switchdin

thanks for the report - yeah iirc going through plotly directly (as opposed to plotly.express) will just convert to numpy, so it would get an array of timestamps at the corresponding utc times?

MarcoGorelli avatar Jun 10 '25 13:06 MarcoGorelli