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floating widget

Open zmoth opened this issue 2 years ago • 0 comments

Sometimes a complex embedded widget will produce a very large node(personally, I think it's ugly). there are also windows that need to be very large, but resize() does not solve our problem, e.g. ImageShowModel.

So I wondered if there could be an option for us to decide if the embedded widget for node actually needs to be embedded in node. bool widgetEmbeded() const { return true; }

Here I have written a simple example. to show the original node and the modified node.

Before: The image size I show here is 1082x602, and to see the detail you need to zoom in to quite a large size, and it is cumbersome to manipulate.

image

After: In this example I don't embed the widget in the node, instead I use a double click on the node to generate the dockwidget. Of course, any window can now call node's embeddedWidget(). If this is the case, I am also able to zoom in and out in the image display, etc.

    connect(
        _scene, &DataFlowGraphicsScene::nodeDoubleClicked, this, [this](QtNodes::NodeId nodeId) {
            QString name = _graphModel->nodeData(nodeId, QtNodes::NodeRole::Type).value<QString>();

            bool isEmbeded =
                _graphModel->nodeData(nodeId, QtNodes::NodeRole::WidgetEmbeded).value<bool>();
            auto w = _graphModel->nodeData(nodeId, QtNodes::NodeRole::Widget).value<QWidget *>();

            if (!isEmbeded && w) {
                QDockWidget *dock = new QDockWidget(name, this);
                dock->setWidget(w);
                this->addDockWidget(Qt::LeftDockWidgetArea, dock);
            }
        });

In addition I can choose whether to embed or not via the bool variable, as there are some very simple widgets that might look better with an embed approach.

image

zmoth avatar Feb 20 '23 01:02 zmoth