script.py without "(" print command
The file script.py is generate without "(" print command , i use pyhton3 ....
`""" Copyright (c) 2011 Michael Elsdoerfer [email protected]
Licensed under the Apache License, Version 2.0 (the "License"); you may not use this file except in compliance with the License. You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software distributed under the License is distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the License for the specific language governing permissions and limitations under the License. """
import sys from os import path import logging
from build import AndroidProject, ProgramFailedError, LOGGER_NAME
def main(argv): scriptname = path.basename(sys.argv[0]) if len(argv) != 1: print "Builds the Android project in the current directory." print "Usage: %s PATH_TO_SDK" % scriptname return 1
# Setup logging
log = logging.getLogger(LOGGER_NAME)
sh = logging.StreamHandler()
sh.setFormatter(logging.Formatter("> %(message)s"))
log.addHandler(sh)
p = AndroidProject('AndroidManifest.xml', sdk_dir=argv[0])
try:
apk = p.build()
keystore = path.expanduser('~/.android/debug.keystore')
if path.exists(keystore):
print "Signing with debug key..."
apk.sign(keystore, 'androiddebugkey', 'android')
apk.align()
else:
print "Note: Package will be unsigned!"
print "Created: %s" % apk.filename
except ProgramFailedError, e:
print u"ERROR: %s" % unicode(e)
print
if e.stdout:
print "STDOUT"
print "------"
print e.stdout
if e.stderr:
print "STDERR"
print "------"
print e.stderr
def run(): sys.exit(main(sys.argv[1:]) or 0)
if name == 'main': run()`