Using Retrying at run time, how can I actually retry without raising exception ?

[GeoffreyJohnen]

Hi,

I'm currently trying to implement Tenacity in a code that use a low-bandwidth communication modem to send data. Here is the pseudo-code :

from tenacity import retry,stop_after_delay,Retrying,stop_after_attempt
import time
import random 


class Sender:

    def __init__(self) -> None:
        self.sending_timeout = 10
        self.sending_retries = 5

    def get_sending_timeout(self):
        return self.sending_timeout

    def sending_emulation(self):
        print("sending...")
        time.sleep(5)
        fail = random.randint(0,5)
        if not fail:
            print("Success !")
        else:
            raise Exception("Could not send!")

    def sending_emulation_timeout(self):
        retryier = Retrying(stop=stop_after_delay(self.sending_timeout),reraise=True)
        retryier(self.sending_emulation(),"test")


if __name__ == "__main__":
    s = Sender()
    s.sending_emulation_timeout()

The amount of retries, and the timeout are specified in a configuration file which are then loaded as attributes. I'd like to use these attributes to modify Retry behavior at run time. My problem in this example, is that sending_emulation_timeout() doesn't actually retries but just re raise the exception. I tried using reraise=False as well, but no luck. How can I make it retry according to the timeout ?

[FyZzyss]

As stated here https://github.com/jd/tenacity#changing-arguments-at-run-time. There should be no method call inside retrayer Your code should be:

    def sending_emulation_timeout(self):
        retryier = Retrying(stop=stop_after_delay(self.sending_timeout), reraise=True)
        retryier(self.sending_emulation)

The Reraise flag affects raise the original error or a specific Tenacity error will be returned