Passing an argument multiple times

[NeveIsa]

How can add argument multiple times?

For example, in the multiply example, how to pass arbitrary number of integers with flags like this -

python calculate.py multiply -x 1 -x 2 -x 3 6

[hacker20028]

To specify an argument multiple times, you can use the argparse library in Python. Here is an example of how you can use argparse to parse a list of integers from the command-line arguments and multiply them:

import argparse

parser = argparse.ArgumentParser()
parser.add_argument('-x', action='append', type=int, help='an integer')

args = parser.parse_args()

result = 1
for x in args.x:
    result *= x

print(result)

You can then call the script with the following command:

python calculate.py multiply -x 1 -x 2 -x 3

This will output 6, which is the result of multiplying 1 * 2 * 3.

Also, note that the -x argument is specified as an append action, which means that it can be specified multiple times on the command line and the values will be stored in a list. The type parameter specifies that the values should be converted to integers.

Hope this Helps.