exaloop
Builtin `min()` does not support argument `key`
I have the following code:
distances = {'a': 4, 'b': 1}
queue = ['a', 'b']
u = min(queue, key=distances.get)
queue.remove(u)
print(queue)
When run with Python 3.11.1, I get the expected result printed:
> python3 min_example.py
['a']
If I try to run it with Codon 0.16.2, I get the following:
> codon run min_example.py
min_example.py:3:20-33: error: 'key' is an invalid keyword argument for min()
Is this expected? I assumed the key parameter would be supported for min().
Thanks for the report -- yes we definitely should support that. We'll plan to have it in the next release!
By the way, this is also the case for max().
For example, for finding the most common letter in letters, this is a short way of writing it:
most_common = max(set(letters), key=letters.count)
Unfortunately this still throws an error in Codon 0.16.3:
error: 'key' is an invalid keyword argument for max()
Hi @akleemans, I've created a PR for this here: https://github.com/exaloop/codon/pull/505 -- it'll be included in the next version that we plan to release in the next couple weeks!
