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the time of job needed will be count for every ?

Open REBOOTERS opened this issue 1 year ago • 0 comments

def job():
    global count
    logger.info("I'm doing a periodic job!" + str(count))
    count = count + 1
    time.sleep(30)


# 每隔 2 分钟执行一次任务
job()
schedule.every(2).minutes.do(job)
while True:
    # logger.info("waiting for")
    schedule.run_pending()
    time.sleep(1)

the log is

2024-03-18 12:03:44,170 - INFO - I'm doing a periodic job!0
2024-03-18 12:06:14,534 - DEBUG - Running job Job(interval=2, unit=minutes, do=job, args=(), kwargs={})
2024-03-18 12:06:14,535 - INFO - I'm doing a periodic job!1
2024-03-18 12:08:44,888 - DEBUG - Running job Job(interval=2, unit=minutes, do=job, args=(), kwargs={})
2024-03-18 12:08:44,889 - INFO - I'm doing a periodic job!2
2024-03-18 12:11:15,267 - DEBUG - Running job Job(interval=2, unit=minutes, do=job, args=(), kwargs={})
2024-03-18 12:11:15,267 - INFO - I'm doing a periodic job!3
2024-03-18 12:13:45,660 - DEBUG - Running job Job(interval=2, unit=minutes, do=job, args=(), kwargs={})
2024-03-18 12:13:45,660 - INFO - I'm doing a periodic job!4

the code want job run every 2 minutes ,but it run every 2:30 minute , include the time the job costed.

Is this as expected? or Bug ?

REBOOTERS avatar Mar 18 '24 04:03 REBOOTERS