refactor: use abs() and inplace operation
n = -n if n < 0 else n --> n = abs(n) n = n // 10 --> n //= 10
Describe your change:
- [ ] Add an algorithm?
- [ ] Fix a bug or typo in an existing algorithm?
- [ ] Documentation change?
Checklist:
- [x] I have read CONTRIBUTING.md.
- [x] This pull request is all my own work -- I have not plagiarized.
- [x] I know that pull requests will not be merged if they fail the automated tests.
- [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms.
- [x] All new Python files are placed inside an existing directory.
- [x] All filenames are in all lowercase characters with no spaces or dashes.
- [x] All functions and variable names follow Python naming conventions.
- [x] All function parameters and return values are annotated with Python type hints.
- [x] All functions have doctests that pass the automated testing.
- [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation.
- [x] If this pull request resolves one or more open issues then the commit message contains
Fixes: #{$ISSUE_NO}.
Did the timeit() benchmarks improve or not?
I would like to avoid this issue https://github.com/TheAlgorithms/Python/pull/7190#issuecomment-1279545707. I think we are ok on this pr.
I still want to make sure that the timeit test show that the proposed solution is faster than the current one.
I would like to avoid this issue #7190 (comment). I think we are ok on this pr.
I do understand where you're coming from, but this is not an optimization, rather a refactor.
I still want to make sure that the timeit test show that the proposed solution is faster than the current one.
There won't be any difference.
There won't be any difference.
Prove it.