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Added Backtracking Program

Open hiitesh1127 opened this issue 3 years ago • 7 comments

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It is one of the most common Backtracking Problems asked during interviews

Describe your change:

  • [x] Add an algorithm?
  • [ ] Fix a bug or typo in an existing algorithm?
  • [ ] Documentation change?

Checklist:

  • [x] I have read CONTRIBUTING.md.
  • [x] This pull request is all my own work -- I have not plagiarized.
  • [x] I know that pull requests will not be merged if they fail the automated tests.
  • [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms.
  • [x] All new JavaScript files are placed inside an existing directory.
  • [x] All filenames should use the UpperCamelCase (PascalCase) style. There should be no spaces in filenames. Example:UserProfile.js is allowed but userprofile.js,Userprofile.js,user-Profile.js,userProfile.js are not
  • [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation.
  • [x] If this pull request resolves one or more open issues then the commit message contains Fixes: #{$ISSUE_NO}.

hiitesh1127 avatar Oct 18 '22 22:10 hiitesh1127

@appgurueu Sir you are correct when there are just two digits in the provided string, but if we analyze the scenario of three digits, we notice that we need to backtrack for the second digit string.

hiitesh1127 avatar Oct 19 '22 08:10 hiitesh1127

@appgurueu Sir you are correct when there are just two digits in the provided string, but if we analyze the scenario of three digits, we notice that we need to backtrack for the second digit string.

I wrote the following solution which got accepted in Go:

func letterCombinations(digits string) []string {
    if digits == "" {
        return []string{}
    }
    letters := [8]string{"abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"}
    res := []string{""}
    for _, digit := range digits {
        nextRes := []string{}
        for _, letter := range letters[digit - '2'] {
            for _, str := range res {
                nextRes = append(nextRes, str + string(letter))
            }
        }
        res = nextRes
    }
    return res
}

this problem does not inherently require recursion or backtracking? As said, it's just the cartesian product $\{a, b, c\} \times \{d, e, f\} \times \{g, h, i\}$ f.E. for $123$.

appgurueu avatar Oct 19 '22 08:10 appgurueu

Okay Sir,

I guess your solution is iterative and mine is recursive My backtracking approach for this solution is we need to backtrack for node no 3's

lettercombination

https://www.interviewbit.com/blog/letter-combinations-of-a-phone-number/

hiitesh1127 avatar Oct 19 '22 08:10 hiitesh1127

Backtracking is a class of algorithm for finding solutions to some computational problems, notably constraint satisfaction problems, that incrementally builds candidates to the solutions, and abandons a candidate as soon as it determines that the candidate cannot possibly be completed to a valid solution.

- from https://en.wikipedia.org/wiki/Backtracking

I don't see how this definition is met - no "candidates" are "abandoned" (if I'm missing something, please explain). All I see is a simple combinatorial algorithm. LeetCode and InterviewBit are probably getting their terminology wrong. @raklaptudirm your opinion? Should this go under "Backtracking" or just "Recursion"?

In the Lua repo I prefer to categorize algorithms not by the applied "strategy", but rather strictly by the problem they solve.

appgurueu avatar Oct 19 '22 08:10 appgurueu

Please review @raklaptudirm

hiitesh1127 avatar Oct 19 '22 22:10 hiitesh1127

I guess recursive would be best.

raklaptudirm avatar Oct 20 '22 14:10 raklaptudirm

I guess recursive would be best.

Okay I will update

hiitesh1127 avatar Oct 20 '22 17:10 hiitesh1127

Done @appgurueu @raklaptudirm

hiitesh1127 avatar Oct 20 '22 20:10 hiitesh1127