openapi-generator
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How to get the request path in code.
While implementing a POST body.
I want to return status of 201 Created along with the URI. However, how do i get the request-path in the first place..
@Override
public ResponseEntity<Void> createPet (Pet p ) {
Pet p1 = petRepository.save(p);
return ResponseEntity.created(" request-path.. ?? " + p1.id); // <-- how can i get the input path here
}
i dont want to hard-code request-path.
- Below is my (pretty regular) pom file.
<plugin>
<groupId>org.openapitools</groupId>
<artifactId>openapi-generator-maven-plugin</artifactId>
<version>7.5.0</version>
<executions>
<execution>
<goals>
<goal>generate</goal>
</goals>
<configuration>
<inputSpecRootDirectory> ${project.basedir}/src/main/resources/openapi
</inputSpecRootDirectory>
<generatorName>spring</generatorName>
<apiPackage>com.example.openapi.api</apiPackage>
<modelPackage>com.example.openapi.model</modelPackage>
<configOptions>
<modelSuffix>Dto</modelSuffix>
<useJakartaEe>true</useJakartaEe>
<library>spring-boot</library>
<delegatePattern>true</delegatePattern>
<hideGenerationTimestamp>true</hideGenerationTimestamp>
<interfaceOnly>true</interfaceOnly>
<useSpringBoot3>true</useSpringBoot3>
<useSpringfox>false</useSpringfox>
</configOptions>
</configuration>
</execution>
</executions>
</plugin>
```
</details>
Hi @kush20. I might misinterpred your question, but if your question is how to get the request path of the request made to the spring controller. I don't think this is a bug of the generator. This is existing Spring functionality, you can use HttpServletRequest to get the request path of the current request handling thread.