处理 if(num == 1 || num == 2 || num == 3){}这种情况用inclide

[Kelichao]

const num = 1;

// LONGER FORM
if(num == 1 || num == 2 || num == 3){
  console.log("Yay");
}

// SHORTHAND
if([1,2,3].includes(num)){
  console.log("Yay");
}